Matematika

Pertanyaan

rumus fungsi f(x) =ax+b dan f(-2)=14dan f(3)=1

1 Jawaban

  • f(-2) = -2a + b = 14
    f(3) = 3a + b = 1
    ______________ -
    -5a = 13
    5a = -13
    a = -13/5

    3a + b = 1
    3(-13/5) + b = 5/5
    -39/5 + b = 5/5
    b = 5/5 - -39/5
    = 44/5

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