rumus fungsi f(x) =ax+b dan f(-2)=14dan f(3)=1
Matematika
Aprillaamedisaa14
Pertanyaan
rumus fungsi f(x) =ax+b dan f(-2)=14dan f(3)=1
1 Jawaban
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1. Jawaban hurufdanangk4
f(-2) = -2a + b = 14
f(3) = 3a + b = 1
______________ -
-5a = 13
5a = -13
a = -13/5
3a + b = 1
3(-13/5) + b = 5/5
-39/5 + b = 5/5
b = 5/5 - -39/5
= 44/5