luas segitiga jika diketahui panjang sisi-sisinya 8cm,12cm,dan16cm adalah.....??

maaf keliru.

t=√(10^2-(16÷2)^2)
=√(100-64)
=√36
=6cm

L=1/2×8×6
=24cm2

s = 1/2 (a + b + c) = 1/2 (8 + 12 + 16) = 1/2 (36) = 18
Luas = √(s (s - a)(s - b)(s - c))
= √(18 . (18 - 8) (18 - 12) (18 - 16))
= √(18 . 10 . 6 . 2)
= √(2160)
= √144 √15
= 12 √15 cm²