jika p(4a,-6)dan q(6a,10)dan gradien garis pq=-4.tentukan:a.nilai a b.koordinat titik p dan q

a)
p(4a, -6)  dan q(6a, 10)
x1 = 4a
y1 = -6
x2 = 6a
y2 = 10

m = -4

m = (y2 - y1) / (x2 - x1)
-4 = (10 -  (-6)) / (6a - 4a)
-4 = 16/2a
-8a = 16
a = 16 : - 8
a = -2

b)
p(4a, -6)
p(4(-2), -6)
p(-8, -6)

q(6a, 10)
q(6(-2), 10)
q(-12, 10)