kerjakan nomor 3 a b dan c mohon dijawab dngn bnr trma kash kls 10

segitiga sama kaki.
a = (8 - 2√2)
b = (4 + √2)
c = (4 + √2)

tinggi segitiga
t² = b² - (a/2)²
t² = (4 + √2)² - (4 - √2)²
t² = 18 + 8√2 - (18 - 8√2)
t² = 16√2
t² = 16 . 2^(1/2)
t² = 2^(9/2)
t = 2^(9/4)

keliling segitiga
K = 2(4 + √2) + (8 - 2√2)
K = 16

luas segitiga
L = 2^(9/4) (8 - 2√2) / 2
L = 2^(9/4) . 2^3  -  2^(9/4) . 2^(3/2)  / 2
L = 2^(17/4) - 2^(11/4)