Tolong cara penyelesaian nomor 1-3. Menggunakan cara penyelesaiannya...

gradien m = 1/2
melalui titik (0,-1)
y - (-1) = (1/2) (x - 0)
y + 1 = x/2
y = x/2 - 2/2
2y = x - 2
x - 2y - 2 = 0

gradien m = -1
melalui (0,3)
y - 3 = -1 (x - 0)
y - 3 = -x
y = -x + 3
x + y - 3 = 0

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kemiringan m = 3/5
melalui (5,9)
y - 9 = (3/5) (x - 5)
y - 9 = 3x/5 - 15/5
y = 3x/5 - 15/5 + 45/5
y = 3x/5 + 30/5
5y = 3x + 30
3x - 5y + 30 = 0

kemiringan m -1/2
melalui (6,3)
y - 3 = (-1/2) (x - 6)
y - 3 = -x/2 + 6/2
y = -x/2 + 6/2 + 6/2
y = -x/2 + 12/2
2y = -x + 12
x + 2y - 12 = 0

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melalui (2,6) dan (-1,-4)
m = (-4 - 6) / (-1 -2)
m = -10/-3
m = 10/3
pers. garisnya
y + 4 = (10/3) (x + 1)
y + 4 = 10x/3 + 1/3
y = 10x/3 + 1/3 - 12/3
y = 10x/3 - 11/3
3y = 10x - 11
10x - 3y - 11 = 0

b.
melalui (1,3) dan (8,-5)
m = (-5 - 3) / (8 - 1)
m = -8/7
pers. garisnya
y - 3 = (-8/7) (x - 1)
y - 3 = -8x/7 + 8/7
y = -8x/7 + 8/7 + 21/7
y = -8x/7 + 29/7
7y = -8x + 29
8x + 7y - 29 = 0