tentukan persamaan garis yng tegak lurus 2y+2=-7/4(x-7) dan melalui titik (-2,-3)

2y + 2 = -7 /4(x-7)
4(2y +2)  = -7 (x-7)
8y + 8 = -7x + 49
8y + 8 + 7x - 49 = 0
8y + 7x -41 = 0
m1 = -a/b
     -7/8
m2 = 8/7
y - y1 = m ( x-x1)
y - (-3) = 8/7 (x -(2))
7(y +3) = 8 (x +2)
7y +21 = 8x + 16
7y - 8x + 21 - 16 =0
7y -8x = -5

2y+2=7/4U +12,5
2y-7/4=12,5+2
2y-7/4= 14,5
sejajar dengan (tingal copi paste trus bolak balik angka di selah kanan=)
2y-7/4u = 2y -7/4u
2y-7/4u= 7/4y-2u
2y-7/4u =7/4 (-3) - 2(-2)
2y-7/4u = 5,25 +4
2y-7/4u = 9,25