Seperangkat kartu bridge tanpa as dikocok dan diambil satu kartu secara acak berapa peluang terambil kartu 10

n(A) = 10 = 1
n(S) = 2,3,4,5,6,7,8,9,J,Q,J = 11

Peluang = n(A) / n(S)
Peluang = 1/11

Semoga membantu dan semoga bermanfaat...

n(S) = 52 - 4 = 48
n(E) = 4
P(E) = n(E) / n(S)
= 4/48
= 1/12