Matematika

Pertanyaan

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1 Jawaban

  • jawab


    (1)
    a)  cos 2c/ (cos c- sin c) = cos c + sin c
    cos 2c / (cos c - sin c) =
    = (cos c + sin c)(cos c - sin c)/(cos c - sin c)
    = cos c + sin c

    b) cot b = csc 2B + cot 2 B
    cot b = cos b/sin b }kalikan (2 cos b/2 cos b)
    = (cos b)(2 cos b)/(2 sin b cos b)
    = 2 cos² b/( sin 2b)
    = (cos 2b + 1)/(sin 2b)
    = cos 2b/sin 2b + 1/sin 2b
    = cot 2b + csc 2b
    = csc 2b + cot 2b

    (2) tan (x/2) = (sin x)/(1+cos x)
    tan (15/2) = (sin 15)/(1 + cos 15)
    sin 15  = sin(45 - 30) = sin 45 cos 30 - cos 45 sin 30
    sin 15 = 1/2 √2 . 1/2 √3 - 1/2 √2 . 1/2
    sin 15 = 1/4(√6 - √2)

    cos 15 = cos(45-30)= cos 45 cos 30 + sin 45 sin 30
    cos 15 = 1/2 √2 . 1/2 √3 + 1/2 √2 . 1/2
    cos 15 = 1/4(√6 + √2)

    tan 7,5 = (sin 15)/(1 + cos 15)
    = 1/4 (√6 - √2) / ( 1 + 1/4(√6 + √2))
    = 1/4 (√6 - √2) / 1/4 ( 4+ (√6 +√2)
    = (√6 - √2) / (4 + √6 + √2)