dik : m=40 kg f=50 n a=60° Uk=0,2 ditanya besar percepatan yang dialami

m = 40 kg
F = 50 N
a = 60°
Uk = 0,2

a . . . . . ?

sigmaFy = 0
N + F sin a - W = 0
N = - F sin a + mg
N = - 50 N sin 60° + 40 kg . 10 m/s²
N = - 50 N . 1/2akar 3 + 400 N
N = - 25 akar 3 N + 400 N

sigmaFx = ma
F cos a - Fg = m a
F cos a - Uk.N = m a
50 N cos 60° - 0,2 .( - 25 akar 3 N + 400 N) = 40 kg . a
50 N . 1/2 + 5 akar 3 N - 80 N = 40 kg a
25 N + 5 akar 3 N - 80 N = 40 kg a
5 akar 3 - 55 N = 40 kg a
a = akar 3/8 - 11/8 m/s²