Matematika

Pertanyaan

cos (alpa+beta).cos (alpa-beta)=cos2 alpa-sin2beta

1 Jawaban

  • Trigonometri.

    cos x cos y = 1/2 [cos (x + y) + cos (x - y)]

    cos (α + β) cos (α - β)
    = 1/2 [cos (α + β + α - β) + cos (α + β - α + β)]
    = 1/2 (cos 2α + cos 2β)
    = 1/2 [(2 cos² α - 1) + (1 - 2 sin² β)]
    = cos² α - sin² β
    Terbukti.

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