Tolong dibantu yaaaa
Matematika
cataleya7
Pertanyaan
Tolong dibantu yaaaa
2 Jawaban
-
1. Jawaban cupid85
11) (y - y1) / (y2 - y1) = (x - X1) / (x2 - X1)
(y - 2) / (4 - 2) = (x - 1) / (3 - 1)
(y - 2) / 2 = (x - 1) / 2
2(y - 2) = 2 (x - 1)
2y - 4 = 2x - 2
2y = 2x - 2 + 4
2y = 2x + 2
y = x + 1 (D)
12) 2y + 2x = 3
2y = - 2x + 3
m = - 2/2 = - 1
sejajar m1 = m2 = - 1
y - y1 = m (x - X1)
y - 6 = - 1 (x - 3)
y = - x + 3 + 6
y = - x + 9 (A)
13) 4y - 3x = 5
4y = 3x + 5
m = ¾
sejajar m1 = m2 = ¾
y - y1 = m (x - X1)
y - 6 = ¾ (x + 3)
y = ¾ x + 9/4 + 6
y = ¾ x + 33/4
4y = 3x + 33 (A)
14) 4y - 6x + 10 = 0
4y = 6x - 10
m = 6/4 = 3/2
tegak lurus
m1 . m2 = - 1
3/2 . m2 = - 1
m2 = - ⅔
y - y1 = m (x - X1)
y + 3 = - ⅔ (x - 4)
y = - ⅔ x + 8/3 - 3
y = - ⅔ x - ⅓
3y = - 2x - 1 (tdk ada opsi) -
2. Jawaban Anonyme
11. D. y=x+1
12. A. y=-x+9
13. A. 4y=3x+33
14. 3y=-2x-1
semoga membantu