1. Seesaikan dengan substitusi a. 2× + y + 5 = 2 Dan 3y + 2× = -5 b. 4× + 3y = 6 dan 2× + y = 3
Matematika
Kartikamaulida95
Pertanyaan
1. Seesaikan dengan substitusi
a. 2× + y + 5 = 2
Dan 3y + 2× = -5
b. 4× + 3y = 6
dan 2× + y = 3
a. 2× + y + 5 = 2
Dan 3y + 2× = -5
b. 4× + 3y = 6
dan 2× + y = 3
2 Jawaban
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1. Jawaban cupid85
a) 2x + y + 5 = 2
2x = - y - 5 + 2
2x = - y - 3
3y + 2x = -5
3y + 2(-y-3) = - 5
3y - 2y - 6 = - 5
y = - 5 + 6
y = 1
2x = - y - 3
2x = - 1 - 3
2x = - 4
x = - 2
hp = {-2,1}
b) 2x + y = 3
2x = - y + 3
4x + 3y = 6
2(-y + 3) + 3y = 6
-2y + 6 + 3y = 6
y + 6 = 6
y = 6 - 6
y = 0
2x = - y + 3
2x = 0 + 3
2x = 3
x = 3/2
hp = {3/2,0} -
2. Jawaban Anonyme
a. hp ={-2,1}
b. hp= {3/2,0}
semoga membantu