Matematika

Pertanyaan

tentang perkalian dan pembagian aljabar, no 4, 5, 6
tentang perkalian dan pembagian aljabar, no 4, 5, 6

1 Jawaban

  • 4a) 3x(2x² - 5y + 4)
    = 6x³ - 15xy + 12x
    b) (3k - 4)(1 - 2k)
    = 3k - 4 + 6k² + 8k
    = 6k² + 11k - 4
    c) (5m + 3)(4m² - m + 6)
    = 20m³ + 12m² - 5m² - 3m + 30m + 18
    = 20m³ + 7m² + 27m + 18
    d) (3 - a)(3a + 4)(a - 2)
    = (9a - 3a² + 12 - 4a)(a - 2)
    = (- 3a² - 13a + 12)(a - 2)
    = - 3a³ + 6a² - 13a² + 26a + 12a - 24
    = - 3a³ - 7a² + 38a - 24

    5) 20xy² ÷ 5xy
    = 4y
    b) 18a²b²c ÷ (-3ab²)
    = (- 6ac)
    c) 12p⁴q³r ÷ 2p³q ÷ 3pr
    = 6pq²r ÷ 3pr
    = 2q²
    d) 15m⁴n³ ÷ (12m³n ÷ 4mn)
    = 15m⁴n³ ÷ 3m²
    = 5m²n³

    6) 8x² + 14x - 15
    -------------------------
    2x + 5
    = (2x + 5)(4x - 3)
    --------------------------
    (2x + 5)
    = 4x - 3

    b) 2x³ - 5x² + 7x - 10
    -------------------------------
    x - 2
    = (x - 2)(2x² - x + 5)
    -----------------------------
    x - 2
    = 2x² - x + 5