yang pinter integral tolong bantuin dong

(t+3)² = t² + 6t + 9

Int [-1, -3] (t² + 6t + 9) dt
=(1/3 t^3 + 3t² + 9t) ¦ [-1 , -3]
= {1/3(-1)^3 + 3(-1)² + 9(-1)} - {1/3(-3)^3 + 3(-3)² + 9(-3)}
= (-1/3 + 3 - 9) - (-9 + 27 - 27)
= 8/3