Nilai ²log 2√2 - (³log 1/9 )² + 7log49 adalah... a.-3/2 b.-1/2 c.1/2 d.3/2 e.15/2 Pake cara ya... Mohon bantuannya ^-^

Bab Logaritma
Matematika SMA Kelas X

^ = pangkat

²log (2√2) - (³log (1/9))² + ⁷log 49
= ²log (2 . 2^(1/2)) - (³log 3⁻²)² + ⁷log 7²
= ²log (2^(1 + 1/2)) - ((-2) . ³log 3)² + 2 . ⁷log 7 
= ²log (2^(3/2)) - (-2 . 1)² + 2 . 1
= (3/2) . ²log 2 - 4 + 2
= (3/2) - 2
= (3/2) - 4/2
= -1/2

jawabannya B