tentukan persamaan garis melalui titik(4,-6)yang tegak lurus dengan garis 8y=6x+6

8y = 6x + 6
4y = 3x + 3
y = 3/4x + 3/4

m1 = 3/4
m2 = -4/3

pers. garis melalui (4,-6)
y - y1 = m (x - x1)
y + 6 = -4/3 (x - 4)
y = -4/3 x + 16/3 + 6 (dikali 3)
3y = -4x + 16 + 18
3y = -4x + 34
4x + 3y - 34 = 0