tolong jawab pertanyaan ini soalnya besok di bawa

3) L1 = p × l
= 22 × 14
= 308 cm²
L2 = ½ × π × r²
= ½ × 22/7 × 7 × 7
= 77 cm²
Lb = 308 - 77 = 231 cm²

4) L1 = ½ × ( a + b) × t
= ½ × (3 + 3 + 14 + 14) × 14
= ½ × 34 × 14
= 238 cm²
L2 = ½ × π × r²
= ½ × 22/7 × 7 × 7
= 77 cm²
Lb = 238 - 77 = 161 cm²

5) L = ½ × (a + b) × t
450 = ½ × (20 + 30) × t
450 = ½ × 50 × t
450 = 25 t
t = 450 ÷ 25
t = 18 cm

3. Luas persegi panjang= 22x14 =308
Luas lingkaran =1/2 Πxrxr= 1/2 x22/7x 7x7=77
Jadi luasnya = 308-77 =231