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Pertanyaan

Fraksi mol dari larutan ure 40℅ berat dengan mr urea 60 dan mr air 18

1 Jawaban

  • wt = 40 gram (Mr = 60)
    wp = 60 gram (Mr = 18)
    Xt = .....?
    Xp = .....?

    nt = wt/Mr = 40/60 = 0,67
    np = wp/Mr = 60/18 = 3,33

    Xt = nt/(nt+np)
    = 0,67/(0,67+3,33)
    = 0,67/4
    = 0,168

    Xp = 1 - Xt
    = 1 - 0,168
    = 0,832

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