Matematika

Pertanyaan

²log(x²+7x-1) = ²log(2x²+2x+5)

1 Jawaban

  • ²log(x² + 7x - 1) = ²log(2x² + 2x + 5)

    x² + 7x - 1 = 2x² + 2x + 5
    x² - 2x² + 7x - 2x - 1 - 5 = 0
    -x² + 5x - 6 = 0
    x² - 5x + 6 = 0
    (x - 3)(x - 2) = 0

    x - 3 = 0
    x = 3

    x - 2 = 0
    x = 2

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