Matematika

Pertanyaan

bayangan titik p(2,-2) oleh translasi t(-5,2)adalah

2 Jawaban

  • [tex]P' = \left[\begin{array}{c}2&-2\\\end{array}\right] + \left[\begin{array}{c}-5&2\\\end{array}\right] [/tex]
    [tex] \left[\begin{array}{c}-3&0\\\end{array}\right][/tex]
    p'(-3;0)
  • P'=[tex] \left[\begin{array}{ccc}x'\\y'\end{array}\right] [/tex]=[tex] \left[\begin{array}{ccc}-5\\2\end{array}\right] [/tex]+[tex] \left[\begin{array}{ccc}2\\-2\end{array}\right] [/tex]=[tex] \left[\begin{array}{ccc}-3\\0\end{array}\right] [/tex]
     Insya Allah

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