persamaan x²-2×-2p=0 mempunyai akar akar m dan n jika m²+n²=24 maka nilai p =

x² - 2x - 2p = 0
m + n = -b/a = -(-2)/1 = 2
mn = c/a = -2p/1 = -2p

m² + n² = 24
(m + n)² - 2mn = 24
2² + 4p = 24
p = (24 - 4)/4
p = 5

m² + n² = (m + n)² - 2mn = 24

m + n = -b/a = 2
m × n = c/a = -2p
2² - 2 × (-2)p = 24
4 + 4p = 24
4p = 24 - 4
4p = 20
p = 5

Sekian, semoga bermanfaat!