persamaan kuadrat 2x²-4×+3=0 mempunyai akar akar a dan b nilai a/b + b/a =

2x² - 4x + 3 = 0
a + b = -(-4)/2 = 2
ab = 3/2

a/b + b/a
= (a² + b²) / ab
= ((a + b)² - 2ab) /ab
= (a + b)²/ab - 2
= 2²/(3/2) - 2
= 8/3 - 6/3
= 2/3